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Math Help - Query

  1. #1
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    Query

    Where possible find all angles between 0 and 2(pi) that satisy the equation?

    cot^2(theta)+5 = 6cot(theta)

    Present your answer in radians

    I got theta = (pi)/4 radians and 3.927 radians.

    Is this correct or are there other solutions?

    Apologies for poor formatting. Unsure how to do otherwise. Theta = angle.

    Many thanks

    Simon



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  2. #2
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    Re: Query

    Quote Originally Posted by bigtumbler View Post
    Where possible find all angles between 0 and 2(pi) that satisy the equation?

    cot^2(theta)+5 = 6cot(theta)

    Present your answer in radians

    I got theta = (pi)/4 radians and 3.927 radians.

    Is this correct or are there other solutions?

    Apologies for poor formatting. Unsure how to do otherwise. Theta = angle.

    Many thanks

    Simon


    \cot^2{\theta} - 6\cot{\theta} + 5 = 0

    (\cot{\theta} - 1)(\cot{\theta} - 5) = 0

    \cot{\theta} = 1

    \theta = \frac{\pi}{4} , \frac{5\pi}{4}

    \cot{\theta} = 5

    \theta = \cot^{-1}(5) = .197 \, , \, \pi + \cot^{-1}(5) = 3.339
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