Thread: Need help with cotangent and tangent functions

Okay, I'm attempting to teach myself Trigonometry, but it's very difficult without a teacher. Could anybody tell me how to graph Tangent functions, and then Cotangent functions? I have the general form of a tangent in my notes, but my calculator doesn't want to cooperate with me. ie: One question I have is "Identify the location of the asymptotes of the function: f(theta)=5cot((3/2)theta-(pi/4))+1"

According to the general form of a tangent, the Period should be |pi/b|, which is pi/(3/2) in this problem. But when I type it into my calculator(TI-83 Plus), it gives me 2.094395102. Now how am I supposed to graph that? Also, this calculator won't let me convert from decimal to fraction for some reason, so I don't know what to do. :/

If anybody can help me with this, I will love them forever. Lol.

Originally Posted by AngusBelrot

Okay, I'm attempting to teach myself Trigonometry, but it's very difficult without a teacher. Could anybody tell me how to graph Tangent functions, and then Cotangent functions? I have the general form of a tangent in my notes, but my calculator doesn't want to cooperate with me. ie: One question I have is "Identify the location of the asymptotes of the function: f(theta)=5cot((3/2)theta-(pi/4))+1"

According to the general form of a tangent, the Period should be |pi/b|, which is pi/(3/2) in this problem. But when I type it into my calculator(TI-83 Plus), it gives me 2.094395102. Now how am I supposed to graph that? Also, this calculator won't let me convert from decimal to fraction for some reason, so I don't know what to do. :/

If anybody can help me with this, I will love them forever. Lol.

Remember that , so in your "Y=" menu, you should type in , then press "Graph". You might also need to adjust your window.

Originally Posted by Prove It

Remember that , so in your "Y=" menu, you should type in , then press "Graph". You might also need to adjust your window.

Why would you put a "5/" at the beginning of the equation? Wouldn't you just type the entire equation in parenthesis, and then press the inverse (x-1) key at the end to get the cotangent?

yes, you can type it in to a TI this way, also ...



Prove it's method is just as valid, and as easy.

Originally Posted by AngusBelrot

Why would you put a "5/" at the beginning of the equation? Wouldn't you just type the entire equation in parenthesis, and then press the inverse (x-1) key at the end to get the cotangent?

Maybe because .