please check my attach and prove it!. It is ms word document.Attachment 23766

Printable View

- May 1st 2012, 09:54 PMsrirahulanTrig
please check my attach and prove it!. It is ms word document.Attachment 23766

- May 2nd 2012, 12:53 AMigniteRe: Trig
$\displaystyle \frac{1}{sec^2x-cos^2x}$

$\displaystyle =\frac{cos^2x}{1-cos^4x}$

$\displaystyle =\frac{cos^2x}{(1-cos^2x)(1+cos^2x)}$

$\displaystyle =\frac{cos^2x}{sin^2x(1+cos^2x)}$

Do similar thing for the other term and simplify.