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Math Help - Trig

  1. #1
    Member srirahulan's Avatar
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    Post Trig

    [1/sec2a-cos2a + 1/cosec2a-sin2a]sin2acos2a = 1-(cos2a)(sin2a)/2+(cos2a)(sin2a)
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  2. #2
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    Re: Trig

    Quote Originally Posted by srirahulan View Post
    [1/sec2a-cos2a + 1/cosec2a-sin2a]sin2acos2a = 1-(cos2a)(sin2a)/2+(cos2a)(sin2a)
    Please put some brackets where they're needed, I can't read this as is.
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