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Math Help - New question that needs help.

  1. #1
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    New question that needs help.

    Here is the question im stuck on.

    solve sec^2 x - (1+rt3)tan x + rt3 = 1 for the range 0< x < 4pi giving the answer in terms of pi.

    Thanks
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  2. #2
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    Quote Originally Posted by novadragon849 View Post
    Here is the question im stuck on.

    solve sec^2 x - (1+rt3)tan x + rt3 = 1 for the range 0< x < 4pi giving the answer in terms of pi.

    Thanks
    \sec^2 x = \tan^2x +1
    Thus,
    \tan^2 x + 1 - (1+\sqrt{3})\tan x + \sqrt{3} = 1
    Thus,
    \tan^2 x -(1+\sqrt{3})\tan x + \sqrt{3} = 0
    Let y=\tan x to get,
    y^2 - (1+\sqrt{3})y+\sqrt{y}=0.
    Use quadradic forumula.
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