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Math Help - Help with Trigonometry CAST Diagram?? PLEASE

  1. #1
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    Wink Help with Trigonometry CAST Diagram?? PLEASE


    I dont know how to do in graph method so if you explain me in CAST that it would be helpful.
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    Re: Help with Trigonometry CAST Diagram?? PLEASE

    what do you mean by "CAST" ???
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    Re: Help with Trigonometry CAST Diagram?? PLEASE

    S A It's a way of remembering which of the trig functions are positive in each quadrant. eg in 4th quadrant Tan is positive and Sine and Cosine are negative.
    T C
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    Re: Help with Trigonometry CAST Diagram?? PLEASE

    S A It's a way of remembering which of the trig functions are positive in each quadrant. eg in 4th quadrant Tan is positive. A stands for all.
    .
    T C
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    Re: Help with Trigonometry CAST Diagram?? PLEASE

    Sorry, that of course should have said in 3rd quadrant Tan is positive.
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    Re: Help with Trigonometry CAST Diagram?? PLEASE

    cant you see the picture?? i posted with the diagram in my first post?
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    Re: Help with Trigonometry CAST Diagram?? PLEASE

    Quote Originally Posted by Sasori View Post
    cant you see the picture?? i posted with the diagram in my first post?
    no, I do not see a picture.
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    Re: Help with Trigonometry CAST Diagram?? PLEASE



    What about now?
    Attached Thumbnails Attached Thumbnails Help with Trigonometry CAST Diagram?? PLEASE-trig.png  
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    Re: Help with Trigonometry CAST Diagram?? PLEASE

    375 is 15 degrees into the first quadrant second time round so cos375 is positive and equal to cos15. So 15 is an answer to the question. Similarly if 735 had come up as an answer it would mean 15 (which is in the required range) is again an answer.
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    Re: Help with Trigonometry CAST Diagram?? PLEASE

    Quote Originally Posted by biffboy View Post
    375 is 15 degrees into the first quadrant second time round so cos375 is positive and equal to cos15. So 15 is an answer to the question. Similarly if 735 had come up as an answer it would mean 15 (which is in the required range) is again an answer.
    Thanks for the help man
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