Finding theta given csc and cot...

Generally a problem such as mine would be quite easy, but instead of given constants, I'm given two trigonometric functions:

$\displaystyle csc\Theta = \frac{x+6}{x-2}$

$\displaystyle cot\Theta = \frac{x+5}{x-2}$

From this I've gathered:

$\displaystyle o = x-2$ (Opposite side length)

$\displaystyle a = x+5$ (Adjacent side length)

$\displaystyle h = x+6$ (Hypotenuse side length)

However I have no clue as to how to go from here. Using the law of cosines would bring me no where I believe. Care to correct me? :P

If it isn't obvious enough already, I'm supposed to solve for $\displaystyle \Theta$.

Thanks everyone!