(sin
^{2}θ-cos
^{2}θ)/(1-tan
^{2}θ)=-cos
^{2}θ
So, the above is the equation that I have to verify.
I think the first step to this equation is
-1 (sin^{2}θ-cos^{2}θ)/(1-tan^{2}θ)=-cos^{2}θ
This is incorrect. You have only multiplied the left hand side by -1.
-1 (-(1))/(-1(sec
^{2}θ)=-cos
^{2}θ <-- So... I hope you can kinda get my train of thought here, but I feel like it's completely wrong (
)
You have been given
If you want to multiply by -1 you have to multiply both the left had side and the right hand side.
1/(-1(sec
^{2}θ) = -cos
^{2}θ
Then by simplifying the above you get -cos
^{2}θ ~ however... the blackboard answer I get to select from... doesn't even have an answer close to what I did above...
Please help