i'm measuring the distance of a boat moored on a 22.5 degree angle being the front nose hard up against the mooring and rear end hanging out on the 22.5 degree angle, i want to know the distance from the mooring of the rear end on the 52 foot boat.
i come up with this model/formula is it right, is there other ways, i know very little about maths.
i worked out (i think) using a model, i took a room 3.5 m X 3.5 m went from one corner diagonally to another corner that gave me the 45 degrees cutting that in half gave me 22.5 degrees? measuring half distance from wall to wall, and being the distance from the 0-180 degree wall line at the 22.5 degree mark was for this scenario 1.75 metres.
being 3500mm (3.5m) and the boat being 15849.6mm (15.84+m) and dividing that with each other gave me 4.52845714+ and times by 1750mm (1.75m)(22.5 degrees) gives me 7.9248m or 79248mm, being the distance (excluding the width of the boat which would add that distance on top of the 7.9m being the further-est distance) of the rear end of the boat away from the mooring, is this right?. or am i wrong, is there an easier way i'm not the worlds best at maths, amerature!.
any help welcome.