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Math Help - Help

  1. #1
    Newbie
    Joined
    Nov 2011
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    12

    Help

    I am trying to simplify the end of this half angle problem

    How do I get from \sqrt{(9-\sqrt{17})/(18)}


    to:


    (1/3)\sqrt{(9-\sqrt{17})/(2)}
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  2. #2
    Junior Member
    Joined
    Mar 2012
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    USA
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    Re: Help

    Working backwards:
    Since the two is on the denominator it is essentially multiplying the (9-(17)^(1/2)) by 1/2. So to get 1/3 into the denominator you would square it, which becomes 1/9. then you would multiply it by everything else which will get the denominator to be 18.

    Working Forwards:

    \sqrt{(9-\sqrt{17})/(18)} =

    \sqrt{(9-\sqrt{17})(1/18)} =

    \sqrt{(9-\sqrt{17})(1/2)(1/9)} =

    (1/3)\sqrt{(9-\sqrt{17})(1/2)} =

    (1/3)\sqrt{(9-\sqrt{17})/(2)}
    Last edited by Xeritas; March 21st 2012 at 01:05 PM.
    Thanks from Mikusboi
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  3. #3
    Newbie
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    Nov 2011
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    Re: Help

    Thank you
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