1. ## Help

I am trying to simplify the end of this half angle problem

How do I get from $\sqrt{(9-\sqrt{17})/(18)}$

to:

$(1/3)\sqrt{(9-\sqrt{17})/(2)}$

2. ## Re: Help

Working backwards:
Since the two is on the denominator it is essentially multiplying the (9-(17)^(1/2)) by 1/2. So to get 1/3 into the denominator you would square it, which becomes 1/9. then you would multiply it by everything else which will get the denominator to be 18.

Working Forwards:

$\sqrt{(9-\sqrt{17})/(18)}$ =

$\sqrt{(9-\sqrt{17})(1/18)}$ =

$\sqrt{(9-\sqrt{17})(1/2)(1/9)}$ =

$(1/3)\sqrt{(9-\sqrt{17})(1/2)}$ =

$(1/3)\sqrt{(9-\sqrt{17})/(2)}$

Thank you