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Math Help - Exact solutions with radians

  1. #1
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    Exact solutions with radians

    Im struggling to get my head around radians, and with this question im lost.

    And if you could explain what you're oing as wel so i can follow on thatd be brilliant.

    Find all exact solutions in radians of
    2cos^2 a + sqrt2 cos a = 0, when 0 _< a _< 2pi


    _< is greater or equal to.

    Fanks!
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  2. #2
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    Re: Exact solutions with radians

    Whynot say u = \cos a then solve 2u^2+\sqrt{2}u = 0
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  3. #3
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    Re: Exact solutions with radians

    So the answer would cos a = pi/4 ?
    Or did i do something wrong.
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  4. #4
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    Re: Exact solutions with radians

    You're close, you should be solving \cos a = 0, \frac{-1}{\sqrt{2}}
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  5. #5
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    Re: Exact solutions with radians

    Dude, any chance you could show your working? Im confused as to how you got there.
    Ill give you a foot rub
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  6. #6
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    Re: Exact solutions with radians

    Quote Originally Posted by FlexedCookie View Post
    Find all exact solutions in radians of
    2cos^2 a + sqrt2 cos a = 0, when 0 _< a _< 2pi
    2\cos^2{a} + \sqrt{2} \cos{a} = 0

    factor ...

    \sqrt{2} \cos{a}(\sqrt{2} \cos{a} + 1) = 0

    now set each factor equal to 0 and finish it.
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  7. #7
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    Re: Exact solutions with radians

    Im so sorry but that just made me even more confused mind putting in your working? Im desperately trying to get my head around how these things are working...
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  8. #8
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    Re: Exact solutions with radians

    Quote Originally Posted by FlexedCookie View Post
    Im so sorry but that just made me even more confused mind putting in your working? Im desperately trying to get my head around how these things are working...
    What do you know about factoring and using the zero product property to solve equations? If you are unfamiliar with this procedure, then I recommend you speak to your instructor.
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  9. #9
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    Re: Exact solutions with radians

    Alrighty i asked but hejust gave me some answer that made even less sense.

    any chance of your working mate? im desperate to figure out how this one works.
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  10. #10
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    Re: Exact solutions with radians

    Can you solve a general quadratic? I.e. do you know that if $\displaystyle \begin{align*} ax^2 + bx + c = 0 \end{align*}$ then $\displaystyle \begin{align*} x = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a} \end{align*}$?

    If so, can you solve $\displaystyle \begin{align*} 2x^2 + \sqrt{2}x = 0 \end{align*}$?
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  11. #11
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    Re: Exact solutions with radians

    I know how to solve the quadratic, its getting it to the quadratic im sucking at.
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  12. #12
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    Re: Exact solutions with radians

    Rightio. Managed to solve the first set of factors by setting it to 0. Got -1/sqrt2

    Having trouble solving the second factor. i have no idea how to solve sqrtcos x +1 =0

    any tips?
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