Printable View
Im struggling to get my head around radians, and with this question im lost.
And if you could explain what you're oing as wel so i can follow on thatd be brilliant.
Find all exact solutions in radians of
2cos^2 a + sqrt2 cos a = 0, when 0 _< a _< 2pi
_< is greater or equal to.
Fanks!
Whynot saythen solve
So the answer would cos a = pi/4 ?
Or did i do something wrong.
You're close, you should be solving
Dude, any chance you could show your working? Im confused as to how you got there.
Ill give you a foot rub :)
Quote:
Originally Posted by FlexedCookie
factor ...
now set each factor equal to 0 and finish it.
Im so sorry but that just made me even more confused :( mind putting in your working? Im desperately trying to get my head around how these things are working...
What do you know about factoring and using the zero product property to solve equations? If you are unfamiliar with this procedure, then I recommend you speak to your instructor.Quote:
Originally Posted by FlexedCookie
Alrighty i asked but hejust gave me some answer that made even less sense.
any chance of your working mate? :( im desperate to figure out how this one works.
Can you solve a general quadratic? I.e. do you know that if $\displaystyle \begin{align*} ax^2 + bx + c = 0 \end{align*}$ then $\displaystyle \begin{align*} x = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a} \end{align*}$?
If so, can you solve $\displaystyle \begin{align*} 2x^2 + \sqrt{2}x = 0 \end{align*}$?
I know how to solve the quadratic, its getting it to the quadratic im sucking at.
Rightio. Managed to solve the first set of factors by setting it to 0. Got -1/sqrt2
Having trouble solving the second factor. i have no idea how to solve sqrtcos x +1 =0
any tips?