1. ## trig graphs

I've already sketched the grpah of y = cosx for 0 <(less than or equal to) x <(less than or equal to) 360 but the problem im having is where it askes me to hence solve negative square root 3 over 2 <(less than or equal to) cosx <(less than or equal to) square root 3 over 2 ==

2. ## Re: trig graphs

So the question is this: for which angles is the following statement true: $-\frac{\sqrt{3}}{2} \leq \cos \theta \leq \frac{\sqrt{3}}{2}$?

To answer that, you must first find the angles for which equality holds.

3. ## Re: trig graphs

how do i find the angles for which equality holds?

4. ## Re: trig graphs

What is:
$\arccos\left(\frac{-\sqrt{3}}{2}\right)$?
$\arccos\left(\frac{\sqrt{3}}{2}\right)$?