How do I check for the number of solutions in a triangle?
As in 1 solution, 2 solutions, or 0 solutions.
If Possible are there formulas to follow that can help me figure this out?
This here is the only stuff I have gotten to check the solutions, but what to do for other situations, I do not know:
If angle A is acute and a<b then there are 3 possibilities.
1. If a>b*sin(A) then there are 2 solutions
2. If a=b*sin(A) then there is 1 solution
3. If a<b*sin(A) then there are 0 solutions.
Wasn't sure how to make it work with obtuse triangles, or right triangles, or triangles that have different letters that are already identified.