Results 1 to 2 of 2

Math Help - diagram 3D

  1. #1
    Junior Member
    Joined
    Nov 2011
    Posts
    53

    diagram 3D

    question: while standing at the left corner of the schoolyard in front of here school, Suzie estimates that the fronth face is 8.9m wide and 4.7 high. From her position. Suzie is 12.0m from the base of the right exterior wall. She determines that the let and the right exterior walls appear to be 39degrees apart. from her position, what is the angle of elevation, to the nearest degree, to the top of the left exterior wall?
    can someone create the 3D diagram and show me how to solve what?
    Follow Math Help Forum on Facebook and Google+

  2. #2
    Super Member

    Joined
    May 2006
    From
    Lexington, MA (USA)
    Posts
    11,713
    Thanks
    632

    Re: diagram 3D

    Hello, ahmedb!

    The description is rather fuzzy; they should have supplied a diagram.
    I hope I've interpreted it correctly/


    Qhile standing at the left corner of the schoolyard in front of her school,
    Suzie estimates that the fronth face is 8.9m wide and 4.7 high.
    From her position, Suzie is 12.0m from the base of the right exterior wall.
    She determines that the left and the right exterior walls appear to be 39 degrees apart.
    From her position, what is the angle of elevation, to the nearest degree,
    . . to the top of the left exterior wall?

    Code:
                    D                   C
                    o - - - - - - - - - o
                   *|                   |
                  * |4.7                |
                 *  |                   |
                *   |       8.9         |
               *    o - - - - - - - - - o
              *   * A             *     B
             *  *           *
            * * 39d   * 12.0
           **   *
        S o
    Rectangle ABCD is the front face of the school.
    . . AB = 8.9,\;AD = 4.7

    Suzie is at point S.\;\;\angle ASB = 39^o,\;SB = 12.0

    We want \angle DSA.


    In \Delta SAB, we have: . AB = 8.9,\;SB = 12.0,\;\angle S = 39^o

    Law of Sines: . \frac{\sin A}{12} \,=\, \frac{\sin 39^o}{8.9} \quad\Rightarrow\quad \sin A \:=\:0.848521876

    Hence: . A \:\approx\:58^o \quad\Rightarrow\quad B \:=\:180^o = 39^o - 58^o \:=\:83^o

    Law of sines: . \frac{S\!A}{\sin83^o} \,=\,\frac{8.9}{\sin39^o} \quad\Rightarrow\quad S\!A \:=\:14.03682588

    Hence: . S\!A \:\approx\:14


    In right triangle D\!AS\!:\;\tan(\angle DSA) \,=\,\frac{4.7}{14} \:=\:0.335714285

    Therefore: . \angle DSA \:=\:18.55763767 \;\approx\;18.6^o

    Follow Math Help Forum on Facebook and Google+

Similar Math Help Forum Discussions

  1. diagram
    Posted in the LaTeX Help Forum
    Replies: 5
    Last Post: December 25th 2011, 04:42 AM
  2. Help with diagram
    Posted in the Algebra Forum
    Replies: 1
    Last Post: April 25th 2010, 12:21 PM
  3. Diagram
    Posted in the Advanced Algebra Forum
    Replies: 2
    Last Post: September 24th 2009, 02:15 PM
  4. Dc and diagram
    Posted in the Geometry Forum
    Replies: 1
    Last Post: January 25th 2008, 04:23 AM
  5. Diagram
    Posted in the Geometry Forum
    Replies: 1
    Last Post: May 8th 2007, 01:46 PM

Search Tags


/mathhelpforum @mathhelpforum