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Math Help - [2sin^2(x/2) ] / [2sin(x/2)cos(x/2)]

  1. #1
    Junior Member
    Joined
    Nov 2011
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    53

    [2sin^2(x/2) ] / [2sin(x/2)cos(x/2)]

    how do you get from:
    [2sin^2(x/2) ] / [2sin(x/2)cos(x/2)]

    to:
    sin(x/2)/cos(x/2)

    ??
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  2. #2
    MHF Contributor Amer's Avatar
    Joined
    May 2009
    From
    Jordan
    Posts
    1,093

    Re: [2sin^2(x/2) ] / [2sin(x/2)cos(x/2)]

    \frac{2\sin ^2 \left(\frac{x}{2}\right) }{ 2 \sin \left(\frac{x}{2}\right)\cos \left\frac{x}{2}\right) } =\frac{2\sin  \left(\frac{x}{2}\right)\sin  \left(\frac{x}{2}\right) }{ 2 \sin \left(\frac{x}{2}\right)\cos \left\frac{x}{2}\right) } = \frac{\sin \left(\frac{x}{2} \right) }{\cos \left(\frac{x}{2}\right)}

    just cancel sin (x/2) and 2
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