how do you get from:

[2sin^2(x/2) ] / [2sin(x/2)cos(x/2)]

to:

sin(x/2)/cos(x/2)

??

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- December 13th 2011, 06:08 AMahmedb[2sin^2(x/2) ] / [2sin(x/2)cos(x/2)]
how do you get from:

[2sin^2(x/2) ] / [2sin(x/2)cos(x/2)]

to:

sin(x/2)/cos(x/2)

?? - December 13th 2011, 06:15 AMAmerRe: [2sin^2(x/2) ] / [2sin(x/2)cos(x/2)]

just cancel sin (x/2) and 2