sinx/(1+cosx) simplify that so it equals: tan(x/2) (1-cosx)/sinx simplify that so it equals: tan(x/2) so can someone post the steps please and thanks
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Originally Posted by ahmedb sinx/(1+cosx) simplify that so it equals: tan(x/2) (1-cosx)/sinx simplify that so it equals: tan(x/2) so can someone post the steps please and thanks start with the basic ratio identity for tangent ... you will also need the half-angle identities for sine ... and cosine ...
You can also use the t-formulas. Let then
no i am not talking about this. i am talking about, sin(x)/(1+cos(x)) when you simplify that you get tan(x/2) so how do you get tan(x/2) from the other equation?
Originally Posted by ahmedb no i am not talking about this. i am talking about, sin(x)/(1+cos(x)) when you simplify that you get tan(x/2) so how do you get tan(x/2) from the other equation? Use the double angle identities to express sin and cos in terms of their half-angles since Let and we arrive at:
i still don't kind of get it can you show the steps?
I still need help
Originally Posted by ahmedb I still need help . In a similar way we get . Use those two in it falls right out.
so what do you do with the (+1)?
Have you tried the suggested substitution in post #8? If you have, you'll soon see what happens to the +1.
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