(sinx)/(1+cosx)=(1-cosx)/(sinx)

simplify so RS=LS

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- December 12th 2011, 07:26 AMahmedbtrig identities
(sinx)/(1+cosx)=(1-cosx)/(sinx)

simplify so RS=LS - December 12th 2011, 07:38 AMPlatoRe: trig identities
- December 12th 2011, 07:39 AMahmedbRe: trig identities
thats not what i am talking about, i am talking about proofs.

like proof that RS=LS by simplifying it - December 12th 2011, 07:40 AManonimnystefyRe: trig identities
hi ahmedb

__Spoiler__: - December 12th 2011, 07:43 AMahmedbRe: trig identities
what did you multiply by 1-cosx?

y can't u use 1-sinx or anything else???

thats what confused me :S - December 12th 2011, 07:47 AManonimnystefyRe: trig identities
when you multiply by 1-sin(x) you don't get anything pretty.by multiplying by 1-cos(x) you get 1-cos^2(x) which you should now is sin^2(x).another way to do this is to multiply the fraction on the RHS by 1+cos(x). :D

- December 12th 2011, 07:49 AMahmedbRe: trig identities
for the RHS why is it 1+cosx??

is there a method like a rule in which you have to follow? - December 12th 2011, 10:25 AMSironRe: trig identities
You can also use

That means for this exercice: