OK: arsin(sin(5p\7)) = 2p/7 arctan(tan(5p/5))= -p/5 Why is the second answer negative?
Follow Math Help Forum on Facebook and Google+
Originally Posted by Nervous OK: arsin(sin(5p\7)) = 2p/7 arctan(tan(5p/5))= -p/5 Why is the second answer negative? The angle must be in the second quadrant...
Originally Posted by Nervous OK: arsin(sin(5p\7)) = 2p/7 arctan(tan(5p/5))= -p/5 Why is the second answer negative? uhhh ... arctan((tan(5pi/5)) = \arctan(tan(pi)) = \arctan(0) = 0
Originally Posted by skeeter uhhh ... arctan((tan(5pi/5)) = \arctan(tan(pi)) = \arctan(0) = 0 I must have misunderstood the question, I thought that p was representing some unknown, not ...
Originally Posted by Prove It I must have misunderstood the question, I thought that p was representing some unknown, not ... first solution is ... arsin(sin(5p\7)) = 2p/7 what else could "p" be?
View Tag Cloud