Results 1 to 7 of 7

Math Help - Trying to determine the height of a weather balloon. I think i have it right

  1. #1
    Newbie
    Joined
    Nov 2011
    Posts
    22

    Trying to determine the height of a weather balloon. I think i have it right

    Two observers 5000m apart, standing at A and B measure the angle of elevation to a weather balloon at H as 47degrees and 71degrees. Find the height of the weather balloon correct to the nearest metre.


    Not certain about my answer to this question. This is what i came up with

    a = c
    Sin A Sin C Sin71= opposite
    5000m*Sin47=a Hypotenuse
    Sin62 Sin71=X
    5000m*Sin47=a 4142sin71
    a=4142 X= 3916

    Is it right ?
    Follow Math Help Forum on Facebook and Google+

  2. #2
    Newbie
    Joined
    Nov 2011
    Posts
    22

    Re: Trying to determine the height of a weather balloon. I think i have it right

    Its gonna be difficult to read. When posting, it manipulates the order that i had written. Now it just disorganized and confusing. Plus i don't know how formulate the math portion.
    Follow Math Help Forum on Facebook and Google+

  3. #3
    Member
    Joined
    Jul 2010
    Posts
    85

    Re: Trying to determine the height of a weather balloon. I think i have it right

    your angles are A = 47, B = 71, C = 62

    5000/ sin 62 = b/ sin 71

    b = 337.83 = 338 m

    sin 47 = x/ 338

    x = 338 x 0.73 = 246. 74 = 247 m
    Follow Math Help Forum on Facebook and Google+

  4. #4
    Newbie
    Joined
    Nov 2011
    Posts
    22

    Re: Trying to determine the height of a weather balloon. I think i have it right

    wouldn't it then be 5000/Sin62*sin71

    If you're right then i guess have some work to do

    Thanks for the help
    Follow Math Help Forum on Facebook and Google+

  5. #5
    MHF Contributor
    skeeter's Avatar
    Joined
    Jun 2008
    From
    North Texas
    Posts
    11,685
    Thanks
    446

    Re: Trying to determine the height of a weather balloon. I think i have it right

    looks like you are correct.

    law of sines ...

    \frac{a}{\sin(71)} = \frac{5000}{\sin(62)}

    a = \frac{5000\sin(71)}{\sin(62)}

    h = a \sin(47) \approx 3916 \, m
    Attached Thumbnails Attached Thumbnails Trying to determine the height of a weather balloon. I think i have it right-triangle.jpg  
    Follow Math Help Forum on Facebook and Google+

  6. #6
    Newbie
    Joined
    Nov 2011
    Posts
    22

    Re: Trying to determine the height of a weather balloon. I think i have it right

    I knew i was right. I should now be able to hand in my work with some confidence.
    Thanks
    Follow Math Help Forum on Facebook and Google+

  7. #7
    Member
    Joined
    Jul 2010
    Posts
    85

    Re: Trying to determine the height of a weather balloon. I think i have it right

    I've just realized that my calculator was in radians so my sin 47, sin 62, sin 71 were not accurate. Your were right.
    Follow Math Help Forum on Facebook and Google+

Similar Math Help Forum Discussions

  1. what is the propability of weather
    Posted in the Statistics Forum
    Replies: 14
    Last Post: April 12th 2013, 07:46 AM
  2. Weather Prediction
    Posted in the Geometry Forum
    Replies: 0
    Last Post: March 23rd 2010, 02:15 PM
  3. weather probability
    Posted in the Statistics Forum
    Replies: 3
    Last Post: January 16th 2010, 06:19 PM
  4. Determine vertical height of a ARC
    Posted in the Geometry Forum
    Replies: 0
    Last Post: January 23rd 2009, 04:45 PM
  5. determine force and height.
    Posted in the Math Topics Forum
    Replies: 3
    Last Post: November 9th 2007, 09:22 AM

Search Tags


/mathhelpforum @mathhelpforum