this appears to be in Q3 not sure what you mean by -π < θ < π.
both of these are in Q3
Given cosecθ= -2, tanθ= 1/3√3 and -π < θ < π.
I must find the exact value of θ in radians, justifying my answer.
It shouldn't be too difficult;
An answer is
cosec theta = -2 implies sin theta = -(1/2); value of tan theta cannot be (1)/(3)√(3) but if it is taken as 1/√(3); then required theta = -(5*pi/6).
Or is this incorrect?