xy-8y^2=63 6x+10y=-3 solve the system by finding the intersection points I graphed the equations on my calculator and got (-11,6) and (11,-7) but I feel like I didn't do it correctly... help?
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Originally Posted by hubbabubba590 xy-8y^2=63 6x+10y=-3 solve the system by finding the intersection points I graphed the equations on my calculator and got (-11,6) and (11,-7) but I feel like I didn't do it correctly... help? Do the points satisfy both functions? Substitute them in and find out. If they do, then they are solutions.
They do not:/
Originally Posted by hubbabubba590 They do not:/ You are right. They do not satisfy the following set of equations: $\displaystyle \begin{cases}xy-8y^2=63 \\ 6x+10y=-3\end{cases}$ Here's the correct graph: As you can see, there are no real solutions.
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