
trig four quadrants
Hello everyone!
I've found the answer to this just need to know if its in the right term
Given that cosec θ = −2, tan θ = 1/3√3
and −π < θ < π, find the exact
value of the angle θ in radians. Justify your answer.
answers are
cosec = 1/sin = 1/2 (which means its in the 3rd or 4th quadrant)
tan = 1/3√3 (which means its in the 1st or 3rd quadrant)
this means that theta is in the 3rd quadrant
but is it 1/6pi or 5/6pi? because each of their values is either +/ 1/6pi but surely that cant be right because 1/6pi is 30 which is not in the 3rd quadrant, could someone just classify this for me! cheers

Re: trig four quadrants
hi emakarov, sorry i don't think i explained very well,
first off i meant (1/3) * √3 which i think is the same as what you wrote 1 / √3
secondly i what i was trying to say was that both these values
sinθ = 1/2 = 1/6pi and
tanθ = 1/√3 = 1/6pi
but this is where i get stuck, because i have two values which are either positive or negative of 1/6 pi and which are neither in the third quadrant so i thought it must be 5/6pi (150 degrees)
but this is where i need help

Re: trig four quadrants
hi skeeter, please explain further. many thanks

Re: trig four quadrants
Thanks for your help emakarov,
That has cleared a lot of things up, looks like I'm going to have to study harder!!