Help with trig addition and subtraction formulas.

If $\displaystyle sin (\alpha) = -\frac {5}{13} $ and $\displaystyle tan ( \alpha) > 0 $ , find the exact value of $\displaystyle sin (\alpha - \frac{\pi}{3}) $.

My first time using latex! Hopefully it makes my problem easier to read.

EDIT:

so the formula is sin(A-B)=(sinA)(cosB)-(cosA)(sinB)

I guess I should mention I know how to get every value except $\displaystyle cos(\alpha)$

and I don't understand why they are telling me $\displaystyle tan ( \alpha) > 0 $

Re: Help with trig addition and subtraction formulas.

sin(A-B)=(sinA)(cosB)-(cosA)(sinB)

using this formula I get sin(A-B) = -$\displaystyle \frac{5}{13}$ * $\displaystyle \frac{\sqrt{3}}{2}$ - cos$\displaystyle (\alpha)$ * $\displaystyle \frac{1}{2}$

Re: Help with trig addition and subtraction formulas.

You have given that $\displaystyle \tan(\alpha)>0$ i.e $\displaystyle \frac{\sin(\alpha)}{\cos(\alpha)}>0$

Re: Help with trig addition and subtraction formulas.

I don't understand. How does that help me find the missing peice $\displaystyle cos(\alpha)$ ?

Re: Help with trig addition and subtraction formulas.

It means that $\displaystyle \cos(\alpha)<0$. I think it can be useful to use the identity $\displaystyle \cos(\alpha)=\pm \sqrt{1-\sin^2(\alpha)}$ (do you see the importance of $\displaystyle \cos(\alpha)<0$ now?)

Re: Help with trig addition and subtraction formulas.

Quote:

Originally Posted by

**dangsos** I don't understand. How does that help me find the missing peice $\displaystyle cos(\alpha)$ ?

it tells you what quadrant $\displaystyle \alpha$ is in ... lets you know whether to make $\displaystyle \cos{\alpha}$ positive or negative.

Re: Help with trig addition and subtraction formulas.

so using $\displaystyle \sqrt{1-sin^2(\alpha)}$ i get cos$\displaystyle (\alpha) = -\sqrt{\frac{144}{169}}$ correct?

Re: Help with trig addition and subtraction formulas.

Normally it has to be $\displaystyle \frac{-12}{13}$

I think you can solve the exercice now ...

Re: Help with trig addition and subtraction formulas.

okay so with all that I get this

sin(A-B) = $\displaystyle - \frac{5}{13} * \frac{\sqrt{3}}{2} - ( \frac{12}{13}) * \frac{1}{2} $

my answer is $\displaystyle - \frac{5 * \sqrt{3} - 12}{26}$

the book gives $\displaystyle \frac{12 * \sqrt{3} - 5}{26} $

Re: Help with trig addition and subtraction formulas.

$\displaystyle \sin{\alpha} \cdot \cos{\frac{\pi}{3}} - \cos{\alpha} \cdot \sin{\frac{\pi}{3}} =$

$\displaystyle -\frac{5}{13} \cdot \frac{1}{2} - \left(-\frac{12}{13}\right) \cdot \frac{\sqrt{3}}{2}$

try again ...

Re: Help with trig addition and subtraction formulas.

I always make the most simple mistakes >.< thank yo ufor correcting me.