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About LinkBacks"Algebraically solve csc x = 2 sin x +1 where
I find myself stuck on this question. Not sure why, it doesn't seem much more complex than what I've been doing. Some help as to what to do would be appreciated.
Originally Posted by DEADTERMINATOR
"Algebraically solve csc x = 2 sin x +1 where
I find myself stuck on this question. Not sure why, it doesn't seem much more complex than what I've been doing. Some help as to what to do would be appreciated. - 1(\sin{x} + 1) \\ 0 &= (\sin{x} + 1)(2\sin{x} - 1) \\ \sin{x} + 1 &= 0 \textrm{ or } 2\sin{x} - 1 = 0 \\ \sin{x} &= -1 \textrm{ or } \sin{x} = \frac{1}{2} \\ x &= 270^{\circ} \textrm{ or } x = \left\{ 30^{\circ}, 150^{\circ} \right\} \\ x &= \left\{ 30^{\circ}, 150^{\circ}, 270^{\circ} \right\}\end{align*} )
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