tan x + cot x = (sin^{2}x + cos^{2}x)/(sin x cos x) = 1 /(sin x cos x) = sec x csc x
Hi all!
I got myself stuck here trying to figure out how to verify this Identity.
tan x + cot x = sec x csc x
Here is what I have so far
tan x + cot x
1/cot x + cot x/1
(1+cot^2)/cot x
(csc x/cot x) * csc x
(1/sin x)/(1/tan x) * csc x
(tan x/sin x) * csc x
But I can't seem to turn (tan x/sin x) into sec x
thankx for helping
ps i'm still new to this so please be as detailed with your responses as you can thanks.
I have another identity I am having trouble with if any1 can help..
(sin x/1-cot x) - (cos x/tan x-1) = sin x + cos x
I was able to clear the denominators but then I am not sure how to go about making the sign positive.
[(sin x/1-cot x)*(tan x-1/tan x-1)] - [(cos x/tan x-1)*(1-cot x/1-cot x)]
= sin x - cos x
thanx