I need to transform the equation (cos(x)^2) + (sin(x)^2) = 1 into 1 + (tan(x)^2) = (sec(x)^2). This was written as though it were through a TI83 calculator.
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Divide both sides by $\displaystyle cos^2(x)$
1/(cos(x)^2) would equal (sec(x)^2), correct? Or would the numerator have to be a 2?
$\displaystyle \frac{1}{cos^2{x}}=sec^2{x}$
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