I'm lost in this question. Find the smallest angle of triangle ABC in which a:b:c = √2 : √3+1 :2
Last edited by Tentaikansokup; Nov 29th 2011 at 07:06 PM.
Follow Math Help Forum on Facebook and Google+
The smallest angle will be opposite the smallest side, which side do you think is the longest? After you know this apply the cosine rule to find the angle.
Last edited by pickslides; Nov 29th 2011 at 06:11 PM.
angle A is the smallest
Yes angle A is the smallest, therefore, $\displaystyle A = \cos^{-1}\left(\frac{b^2+c^2-a^2}{2bc}\right)$
Oh I see.....so that's actually nothing complicated to this question! I've always overlooked things. And I believe the answer is 30 degrees. Thank you so much!
View Tag Cloud