Solve the Equation exactly over the interval [0, 2pi]
the problems i do not understand are:
2sin^2x + sin x - 1 = 0
2sinx cosx + cos(x) = 0
2sin^2x - sin x = 0
if anyone could help me i would appreciate it alot. thanks
Solve the Equation exactly over the interval [0, 2pi]
the problems i do not understand are:
2sin^2x + sin x - 1 = 0
2sinx cosx + cos(x) = 0
2sin^2x - sin x = 0
if anyone could help me i would appreciate it alot. thanks