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Math Help - Secant, and cosecant angles

  1. #1
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    Secant, and cosecant angles

    Hi!
    I have trouble dealing with secΘ and cotΘ.

    1. If sinΘ = -1 √2 and 270 < Θ < 360, find the values of secΘ and cotΘ
    2. If cosΘ = -24 25 and sinΘ<0, find the values of secΘ and cotΘ

    I know that -1 √2 can be -45 or 225 or 585, but it doesn't fall under the condition 270 < Θ < 360. Then I got stuck.....
    Last edited by Tentaikansokup; November 27th 2011 at 02:55 PM.
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  2. #2
    Super Member Quacky's Avatar
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    Re: Secant, and cosecant angles

    \sin\theta=\frac{-1}{\sqrt{2}}

    Taking \theta=-45 and knowing that \cos(-x)=\cos(x) makes this fairly straightforward once you've used the unit circle.

    For \cos\theta =\frac{-24}{25}, consider a 7, 24, 25 right triangle and the property -\sin\theta=\sin{(-\theta)} combined with the one mentioned previously. I think this is all you should need to get a solution.
    Last edited by Quacky; November 27th 2011 at 03:10 PM.
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  3. #3
    Super Member Quacky's Avatar
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    Re: Secant, and cosecant angles

    It would help if I'd read the OP carefully before replying. Corrected my previous response.
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  4. #4
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    Re: Secant, and cosecant angles

    Quote Originally Posted by Quacky View Post
    \sin\theta=\frac{-1}{\sqrt{2}}

    Taking \theta=-45 and knowing that \cos(-x)=\cos(x) makes this fairly straightforward once you've used the unit circle.

    For \cos\theta =\frac{-24}{25}, consider a 7, 24, 25 right triangle and the property -\sin\theta=\sin{(-\theta)} combined with the one mentioned previously. I think this is all you should need to get a solution.
    Thank you so much for your help!!

    And this is what I got.....
    1. Sec(-1 √2) = √2
    Cot(-1 √2) = -1

    2. Sec(-24 25) ~ -1.04
    Cot(-24 25) ~ 3.4
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