Hi forum,
I've got a question - What is tan^-1(cot(x))? My calculator gives me a senseless answer.
Thanks.
1. Go back to the basics. Use a right triangle (see attachment)
2. $\displaystyle \tan(A)=\frac ab~\implies~\tan^{-1}\left(\frac ab\right) = A$
3. $\displaystyle \angle(A)+\angle(B)=\frac \pi2$
4. $\displaystyle \cot(A)=\frac ba = \tan(B)$
5. ... and now you are able to determine $\displaystyle \tan^{-1}(\cot(A))$