Hi forum,

I've got a question - What is tan^-1(cot(x))? My calculator gives me a senseless answer.

Thanks.

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- Nov 25th 2011, 11:30 PMqwertyuiopTrig ratios
Hi forum,

I've got a question - What is tan^-1(cot(x))? My calculator gives me a senseless answer.

Thanks. - Nov 25th 2011, 11:53 PMearbothRe: Trig ratios
1. Go back to the basics. Use a right triangle (see attachment)

2. $\displaystyle \tan(A)=\frac ab~\implies~\tan^{-1}\left(\frac ab\right) = A$

3. $\displaystyle \angle(A)+\angle(B)=\frac \pi2$

4. $\displaystyle \cot(A)=\frac ba = \tan(B)$

5. ... and now you are able to determine $\displaystyle \tan^{-1}(\cot(A))$ - Nov 26th 2011, 12:38 AMqwertyuiopRe: Trig ratios
Ok... I see... kinda...

x=tan^-1(cot(x))

x=tan^-2(tan(pi/2-x))

x=pi-x

Yes? - Nov 26th 2011, 10:48 PMearbothRe: Trig ratios
- Nov 27th 2011, 12:42 AMqwertyuiopRe: Trig ratios
Sorry, that's what i meant :D

Thank you!