Results 1 to 6 of 6

Math Help - triangle height problem from web

  1. #1
    Senior Member
    Joined
    Jul 2010
    Posts
    299
    Thanks
    1

    triangle height problem from web

    Hi;
    The question states.

    AB is a line 652 feet long on one bank of a stream, and C is a point on the opposite bank. A = 53 18', and B = 48 36'. Find the width of the stream from C to AB.

    They get 345.43 feet.

    I get 398.1 feet.

    Pretty sure I'm right (gob smacked if I'm not).

    Just need it confiming.

    Thanks.
    Follow Math Help Forum on Facebook and Google+

  2. #2
    MHF Contributor
    Joined
    Oct 2009
    Posts
    5,417
    Thanks
    718

    Re: triangle height problem from web

    The angles are: A = 53.3, B = 48.6 and C = 78.1. Then the height is \frac{AB}{\sin C}\sin A\sin B\approx 400.739.
    Follow Math Help Forum on Facebook and Google+

  3. #3
    Senior Member
    Joined
    Jul 2010
    Posts
    299
    Thanks
    1

    Re: triangle height problem from web

    How is angle A=53.3 when it says 53.18.
    Follow Math Help Forum on Facebook and Google+

  4. #4
    MHF Contributor
    Joined
    Oct 2009
    Posts
    5,417
    Thanks
    718

    Re: triangle height problem from web

    53 18' means 53 degrees and 18 minutes, i.e., 53 + 18/60 degrees.
    Follow Math Help Forum on Facebook and Google+

  5. #5
    Senior Member
    Joined
    Jul 2010
    Posts
    299
    Thanks
    1

    Re: triangle height problem from web

    Yeah need to read about minutes and seconds.
    Follow Math Help Forum on Facebook and Google+

  6. #6
    Super Member
    earboth's Avatar
    Joined
    Jan 2006
    From
    Germany
    Posts
    5,807
    Thanks
    116

    Re: triangle height problem from web

    Quote Originally Posted by anthonye View Post
    Hi;
    The question states.

    AB is a line 652 feet long on one bank of a stream, and C is a point on the opposite bank. A = 53 18', and B = 48 36'. Find the width of the stream from C to AB.

    They get 345.43 feet.

    I get 398.1 feet. <--- that's definitely wrong

    Pretty sure I'm right (gob smacked if I'm not).

    Just need it confiming.

    Thanks.
    You have used 53.18 or 48.36 respectively instead of 53^\circ+\tfrac{18}{60}^\circ = 53.3^\circ or 48^\circ+\tfrac{36}{60}^\circ = 48.6^\circ

    Compare emakarov's reply!
    Follow Math Help Forum on Facebook and Google+

Similar Math Help Forum Discussions

  1. height of the triangle over the vectors
    Posted in the Advanced Algebra Forum
    Replies: 0
    Last Post: January 11th 2012, 04:18 AM
  2. Working out height of a isosceles triangle
    Posted in the Geometry Forum
    Replies: 4
    Last Post: December 16th 2009, 01:01 PM
  3. Triangle Height
    Posted in the Trigonometry Forum
    Replies: 2
    Last Post: June 1st 2009, 01:51 PM
  4. Triangle height?!
    Posted in the Geometry Forum
    Replies: 5
    Last Post: December 5th 2007, 07:12 PM
  5. height of point on a triangle
    Posted in the Calculus Forum
    Replies: 0
    Last Post: September 18th 2007, 07:30 AM

Search Tags


/mathhelpforum @mathhelpforum