hello i would like to find the smallest angle in degrees from the equation
i think that i need the identity sin^2θ=cos^2θ=1 to solve this and i was then unsure where to head to next either squaring the equation to match the identity or because there is no powers on either side working it out as sin^2θ=1-cos^2θ which i put like
could someone please tell me if i am going right in any way and what the next steps are that i have to take....without to many calculations so i can have another go to understand thanks olie
thankyou for your help. you use t in your formula what does it represent? also i have read up on this method but i keep getting stuck im trying to get two angles within the range 0-360 degrees i looked at a formula close to this which is to write the formula as Rcos(x-a)(or Rsin(x-a) i get the almost there when
x-a = arcsin(3/square root 13) then the results don't match yours, i also don't understand why you subtracted arctan(2/3) at the end.
in the example i have read they get an angle closer to 0 and an angle closer to 360 please can you help me understand a bit further please i thought i was nearly there a few times but don't quite make it each time.