Hey, here is the problem.
In triangle ABC, side "a" is twice as long as side "b". If the hypotenuse is 30cm long, solve the triangle.
If you could please explain to me how to solve this, it would be much appreciated.
Let side 'b' be $\displaystyle x$cm
Then, label each side of the triangle with respect to $\displaystyle x$.
Then use Pythagoras' theorem.
Edit: It will be easier to let side b be $\displaystyle x$cm, rather than side a, as I had suggested initially.
ok so would the equation to solve this value be:?
$\displaystyle x^2 + 2x^2 = 30cm^2 $
and if so, how do I find the value of X?
sorry for all the questions, this question doesn't seem like it should he hard, but its giving me trouble for some reason.
$\displaystyle a = 2b$In triangle ABC, side "a" is twice as long as side "b". If the hypotenuse is 30cm long, solve the triangle.
$\displaystyle a^2 + b^2 = 30^2$
$\displaystyle (2b)^2 + b^2 = 30^2$
$\displaystyle 5b^2 = 30^2$
$\displaystyle b^2 = \frac{30^2}{5}$
$\displaystyle b = \frac{30}{\sqrt{5}} = 6\sqrt{5}$
the sides are ...
$\displaystyle a = 12\sqrt{5}$
$\displaystyle b = 6\sqrt{5}$
$\displaystyle c = 30$