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Trigonometry Problem: BP1 = BP2

http://www.mathhelpforum.com/math-he...1&d=1321130450

How do you resolve this one?

What i got till now:

BP1= 16+12/tanx

BP2= 12+16tanx

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BP1=BP2 = 16+12/tanx = 12+16tanx = (...) = 4tanx - 16tanx2 +12=0

Is it correct?

All you have to do is resolve the equation, find tanx, then sinx and cosx and subsitute them in C(x)?

Thanks in advance!

Re: Trigonometry Problem: BP1 = BP2

I think that you're making this more complicated than it has to be. BP1=BP2. Can't you just use this to show that tanx=1?

Re: Trigonometry Problem: BP1 = BP2