Given that cosec A=-2, tan A=√3÷3 and −π <A<π, find the exact value of the angle A in radians. Justify your answer.
Many Thanks for your prompt reply!
This doesn't ring any bells. Isn't that (what you've said) with relation to a circle? I don't understand how you've come up with this? Super confused now!
Can you solve it? Show me how you see this from my question.
Any further response will be greatly appreciated.
if you know your unit circle as you should ...
$\displaystyle \csc{A} = -2 \implies \sin{A} = -\frac{1}{2}$
$\displaystyle A = -\frac{\pi}{6}$ or $\displaystyle A = -\frac{5\pi}{6}$
$\displaystyle \tan{A} = \frac{\sqrt{3}}{3}$
$\displaystyle A = \frac{\pi}{6}$ or $\displaystyle A = -\frac{5\pi}{6}$
so ... what's that tell you?