I'm having a bit of trouble solving this trig problem:
At first when I looked at it it seemed easy but as I tried to solve it, it got really confusing and I got stuck on the part.Find the General solution for...
Here's what I did:
Double angle formula:
Double angle formula:
Now I can get the general solution for the part but what about the part? How would I solve that?
EDIT: Sorry I just realised I placed this in the wrong section :/
Can a mod please move it to the trig section?
This was an old exam question so we're not allowed to use technology to solve it, just our brains.
Although I guess you can guess one solution by trial and error for the cubic where and try to derive the other solutions from it by factoring.
Thanks for the help!
Hello, Educated!
Here's a little help . . .
Since , then and are in the same right triangle.
Hence: .Code:* /| /x| / | / | / | / | /4x | * - - - *
I know . . . I oversimplified the problem.
. . But you can generalize the solution, right?