Can anyone explain this to me?

A wheel has a radius of 20 cm. If it rolls 60 cm without slipping, through how many radians has it turned?

thanks!

2. Originally Posted by jabbott
Can anyone explain this to me?

A wheel has a radius of 20 cm. If it rolls 60 cm without slipping, through how many radians has it turned?

thanks!
circumference = 2pi(r) = 2pi(20) cm.

It rolls 60 cm, so,
60/[2pi(20)] = 3/(2pi) revolutions.

one revolution is 2pi, so,
[3/(2pi) rev]*[2pi / rev]
= 3

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Another way.

One turn = 2pi radians ===>one circumference = 2pi(20) = 40pi cm.
Let x = radians turned in traveling 60 cm.
So, by proportion,
2pi/(40pi) = x/60
Cross multiply,
2pi(60) = (40pi)x
120pi = 40pi(x)