Find of something

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- September 15th 2007, 03:53 PM #1

- Joined
- Sep 2007
- Posts
- 26

## cot^(2)x??

Ok, so I have this math question that asks find the values of x in radian in the interval [0,2pi] such that 3cot^(2)x=1, and im getting stuck, but this is what I have so far..

cot^(2)x=1/3

cos^(2)x/sin^(2)x=1/3

and now how do i get rid of the squared?

- September 15th 2007, 04:07 PM #2