Can someone explain to me how cos(theta/2) can be recongfigured into The square root of (1/2+ cos(theta)/2). Thanks.
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Originally Posted by jarny Can someone explain to me how cos(theta/2) can be recongfigured into The square root of (1/2+ cos(theta)/2). Thanks. We can use the double angle formula to get it: So we have: solving for we obtain the desired result
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