If then (1)
Offcourse there're infinite solutions for responding to that, but there's given that
Substitute (1) in
But you can't call it an equation because is not equated to anything ... ?
Hi. I have a problem solving this trigonometrical equation:
6sin(pi+x)+cos(pi/2+x) if cosx=0.6 and 0<x<pi/2
If you can, please ask questions so that I try to answer them myself and solve the equation step by step. I'm not from an English speaking country, but I hope we have similar terms and you understand me.
Do I reduce first? I get -7sinx, but I'm not sure how to use then cosx=0.6, if I reduce -7sinx back to cos I get -7cos(3pi/2+x) here also I don't know how to use cosx=0.6....
I got -7sinx because I reduced 6sin(pi+x) and because it's the 3rd quarter (pi<x<3pi/2) sin is negative. I then reduced cos(pi/2+x), since it's 90 degrees it changes its name into sin, and it's the 2nd quarter and in the 2nd quarter cos is negative, so -6sinx-sinx=-7sinx (right?)
What does [] in this case mean? But I'd have square in this case arccos0.6, no?
It's
Here it is calculated by WolframAlpha
I don't know how to explain but 6sin(pi+x) can be reduced to -6sinx ....