Hello, pierce!

I believe your diagram is wrong . . .

A ship leaves port at 10 mph with a heading of N 35° W.

There is a warning buoy located 5 miles directly north of the port.

What is the bearing of the warning buoy **as seen from the ship** after 7.5 hours?

Now I have drawn a diagram and solved that the angle should be 52.7 degrees.

. . Exactly where is that angle?

I just can't figure out what direction.

is it N 52.7 W or would it be N 52.7 E?

How can be the port be to the upper-left or upper-right?

After 10 hours, the ship has traveled 75 miles.

The diagram should look like this:

Code:

X
*
:
:
: Y
S * *
: * * :
: * * :
: * * :
* 75 * * B
Z * |
*35d|5
* |
*
P

The port is at

The ship is at

The buoy is at

Law of Cosines:

. .

. . .

Law of Sines:

. .

. . . .

We see that is obtuse: .

Then: .

Therefore, the heading of the buoy from the ship is: .