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Math Help - Find the value of cot^-1 given arctan

  1. #1
    Junior Member freestar's Avatar
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    Find the value of cot^-1 given arctan

    a = cot^-^1(x) given tan^-^1(x) = \frac{\pi}{4}

    a = ?

    No idea where to start I am guessing cot^-^1 = \frac{1}{tan^-^1} but that is probably wrong. Help.

    Edit: also tried

    \frac{1}{tan(a)}=x

    x = tan (\frac{\pi}{4}) = 1

    \frac{1}{tan(a)} = 1

    tan(a) = 1

    a = tan^-^11

    a = \frac{\pi}{4}

    Not sure if it's right though. Can someone verify please?
    Last edited by mr fantastic; September 18th 2011 at 08:36 PM. Reason: Title.
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  2. #2
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    Find the value of cot^-1 given arctan

    Quote Originally Posted by freestar View Post
    a = cot^-^1(x) given tan^-^1(x) = \frac{\pi}{4}
    a = ?
    No idea where to start I am guessing cot^-^1 = \frac{1}{tan^-^1} but that is probably wrong. Help.
    Edit: also tried
    \frac{1}{tan(a)}=x
    x = tan (\frac{\pi}{4}) = 1
    \frac{1}{tan(a)} = 1
    tan(a) = 1
    a = tan^-^11
    a = \frac{\pi}{4}
    Not sure if it's right though. Can someone verify please?
    I really have no idea what any of that means.

    But: \text{arccot}(x)=\text{arccot}(0)-\arctan(x).
    Last edited by mr fantastic; September 18th 2011 at 08:36 PM. Reason: OP re-titled.
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