Have been tearing my hair out over this for hours...
If you were to hit a cricket-ball a distance of x metres and to a height of x metres, what would be the angle between the ball and the ground upon hitting it. You're expected to assume that the ball doesn't bounce and that g=9.8. Any help, even a point in the right direction, would be greatly appreciated.
I realise that, I've tried every imaginable suvat equation for every possible direction of motion but I'm still no closer. Is there any way to do it by differentiation or something more graphical than plugging in equations?
The ball reaches a maximum height of metres, and travels metres horizontally. So if you use the point where the ball is hit as the origin, the turning point is at .
So substitute these into the equation , where is the turning point, and solve for , then you have the equation of your parabola.
Now, the angle made at the origin will be the same as the angle to the tangent at the origin... You should know that for a straight line ...
So I've found a in terms of x, but I'm not sure how to use this equation. Do I differentiate it? I realise this is probably embarrassingly easy but please bear with me, thanks for your help so far.