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Math Help - Solve Trigo Equation

  1. #1
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    Solve Trigo Equation

    cos(x+0.2)=0.6 for -180<x<180

    x+0.2= cos^-1 0.6
    = 53.13 degrees(base angle)

    What do you do with the 0.2? Do you just minus it straight away? Or do you have to change it to degrees first
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  2. #2
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    Re: Solve Trigo Equation

    hello there
    first of all u have two solutions the first of which u already have
    the second is just the minus of the first
    .... if 0.2 is in radians then either u turn the +-53.13 into radians or
    u turn the 0.2 into degrees
    by the way the solution should have been +-53.13 +360k where k=0,+-1,+-2....
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  3. #3
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    Re: Solve Trigo Equation

    Quote Originally Posted by fuzzy View Post
    cos(x+0.2)=0.6 for -180<x<180

    x+0.2= cos^-1 0.6
    = 53.13 degrees(base angle)

    What do you do with the 0.2? Do you just minus it straight away? Or do you have to change it to degrees first
    you sure the original problem was not in radians? i.e. ...

    -\pi < x < \pi

    \cos(x+0.2) = 0.6

    x = -0.2 \pm \arccos(0.6)
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  4. #4
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    Re: Solve Trigo Equation

    Thank You!
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