1. ## Solve Trigo Equation

cos(x+0.2)=0.6 for -180<x<180

x+0.2= cos^-1 0.6
= 53.13 degrees(base angle)

What do you do with the 0.2? Do you just minus it straight away? Or do you have to change it to degrees first

2. ## Re: Solve Trigo Equation

hello there
first of all u have two solutions the first of which u already have
the second is just the minus of the first
.... if 0.2 is in radians then either u turn the +-53.13 into radians or
u turn the 0.2 into degrees
by the way the solution should have been +-53.13 +360k where k=0,+-1,+-2....

3. ## Re: Solve Trigo Equation

Originally Posted by fuzzy
cos(x+0.2)=0.6 for -180<x<180

x+0.2= cos^-1 0.6
= 53.13 degrees(base angle)

What do you do with the 0.2? Do you just minus it straight away? Or do you have to change it to degrees first
you sure the original problem was not in radians? i.e. ...

$-\pi < x < \pi$

$\cos(x+0.2) = 0.6$

$x = -0.2 \pm \arccos(0.6)$

Thank You!