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Math Help - Understanding the question being asked

  1. #1
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    Understanding the question being asked

    Please don't try to answer the question for me mathematically, I would just like someone to advise me what the question is asking me?

    I am asked to find the area of the triangle AMB, which I have. Then I am asked to find the area of sector AMB, after converting the degrees of the sector 70 to radians. which is to me the same as finding the area of the triangle AMB?

    what am I no seeing here?

    Thanks

    David
    Last edited by David Green; September 12th 2011 at 12:29 PM.
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  2. #2
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    Re: Understanding the question being asked

    Is AM = BM? Is the arc part of a circle?
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  3. #3
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    Re: Understanding the question being asked

    I see the same as you. Usually this kind of question is the typical "find the area of the shaded section" question.
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  4. #4
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    Re: Understanding the question being asked

    @Green
    Study this web page.
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    Re: Understanding the question being asked

    Quote Originally Posted by pickslides View Post
    Is AM = BM? Is the arc part of a circle?
    Hi, yes AM = BM

    I have calculated the lengthof the arc but I now require to know how to use the area of the triangle to find the area of the shaded section?
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    Re: Understanding the question being asked

    Quote Originally Posted by David Green View Post
    Hi, yes AM = BM

    I have calculated the lengthof the arc but I now require to know how to use the area of the triangle to find the area of the shaded section?
    The area of a sector is \dfrac{1}{2}r^2 \theta (for radians)

    The area of a triangle is \dfrac{1}{2}ab \sin C (again, for radians)

    In your case r = a = b = AM = BM = 8 \text{  and  } C = \dfrac{7\pi}{18}
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    Re: Understanding the question being asked

    Quote Originally Posted by e^(i*pi) View Post
    The area of a sector is \dfrac{1}{2}r^2 \theta (for radians)
    Because the proportion of the circle's area being evaluated is \displaystyle \frac{\theta}{2\pi}, which means that the area of that circular sector is \displaystyle \frac{\theta}{2\pi} \times \pi r^2 = \frac{1}{2}r^2\theta
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