I need a little help here !!!
Find the following values exactly:
a) sin (7pi/6) I got -1/2 but i don't know how i got it please someone explain
b) sin (-11pi/4)
2) Find the general soln of the trig eqn
3cosx = 2sin^2x
My answer is : (2 cos x - 1) (cos x + 2) is that right ?