\frac{tgx-sinx}{sin^3x}=\frac{1}{cosx(1+cosx)}
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Originally Posted by deathmate \frac{tgx-sinx}{sin^3x}=\frac{1}{cosx(1+cosx)} What are you trying to do?
Originally Posted by Prove It What are you trying to do? make equal ,left hand like right hand ,my apologies!
first of all you should put [TEX][/TEX] tags because not everyone can read LaTeX input form.
Originally Posted by deathmate make equal ,left hand like right hand ,my apologies! Impossible, where are the t and g on the RHS?
in some countries tgx is the different notation of tanx.
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